Type VectorLaplaceDiag
Namespace tensorflow.contrib.distributions
Parent VectorLaplaceLinearOperator
Interfaces IVectorLaplaceDiag
The vectorization of the Laplace distribution on `R^k`. The vector laplace distribution is defined over `R^k`, and parameterized by
a (batch of) length-`k` `loc` vector (the means) and a (batch of) `k x k`
`scale` matrix: `covariance = 2 * scale @ scale.T`, where `@` denotes
matrix-multiplication. #### Mathematical Details The probability density function (pdf) is, ```none
pdf(x; loc, scale) = exp(-||y||_1) / Z,
y = inv(scale) @ (x - loc),
Z = 2**k |det(scale)|,
``` where: * `loc` is a vector in `R^k`,
* `scale` is a linear operator in `R^{k x k}`, `cov = scale @ scale.T`,
* `Z` denotes the normalization constant, and,
* `||y||_1` denotes the `l1` norm of `y`, `sum_i |y_i|. A (non-batch) `scale` matrix is: ```none
scale = diag(scale_diag + scale_identity_multiplier * ones(k))
``` where: * `scale_diag.shape = [k]`, and,
* `scale_identity_multiplier.shape = []`. Additional leading dimensions (if any) will index batches. If both `scale_diag` and `scale_identity_multiplier` are `None`, then
`scale` is the Identity matrix. The VectorLaplace distribution is a member of the [location-scale
family](https://en.wikipedia.org/wiki/Location-scale_family), i.e., it can be
constructed as, ```none
X = (X_1,..., X_k), each X_i ~ Laplace(loc=0, scale=1)
Y = (Y_1,...,Y_k) = scale @ X + loc
``` #### About `VectorLaplace` and `Vector` distributions in TensorFlow. The `VectorLaplace` is a non-standard distribution that has useful properties. The marginals `Y_1,..., Y_k` are *not* Laplace random variables, due to
the fact that the sum of Laplace random variables is not Laplace. Instead, `Y` is a vector whose components are linear combinations of Laplace
random variables. Thus, `Y` lives in the vector space generated by `vectors`
of Laplace distributions. This allows the user to decide the mean and
covariance (by setting `loc` and `scale`), while preserving some properties of
the Laplace distribution. In particular, the tails of `Y_i` will be (up to
polynomial factors) exponentially decaying. To see this last statement, note that the pdf of `Y_i` is the convolution of
the pdf of `k` independent Laplace random variables. One can then show by
induction that distributions with exponential (up to polynomial factors) tails
are closed under convolution. #### Examples
Show Example
import tensorflow_probability as tfp tfd = tfp.distributions # Initialize a single 2-variate VectorLaplace. vla = tfd.VectorLaplaceDiag( loc=[1., -1], scale_diag=[1, 2.]) vla.mean().eval() # ==> [1., -1] vla.stddev().eval() # ==> [1., 2] * sqrt(2) # Evaluate this on an observation in `R^2`, returning a scalar. vla.prob([-1., 0]).eval() # shape: [] # Initialize a 3-batch, 2-variate scaled-identity VectorLaplace. vla = tfd.VectorLaplaceDiag( loc=[1., -1], scale_identity_multiplier=[1, 2., 3]) vla.mean().eval() # shape: [3, 2] # ==> [[1., -1] # [1, -1], # [1, -1]] vla.stddev().eval() # shape: [3, 2] # ==> sqrt(2) * [[1., 1], # [2, 2], # [3, 3]] # Evaluate this on an observation in `R^2`, returning a length-3 vector. vla.prob([-1., 0]).eval() # shape: [3] # Initialize a 2-batch of 3-variate VectorLaplace's. vla = tfd.VectorLaplaceDiag( loc=[[1., 2, 3], [11, 22, 33]] # shape: [2, 3] scale_diag=[[1., 2, 3], [0.5, 1, 1.5]]) # shape: [2, 3] # Evaluate this on a two observations, each in `R^3`, returning a length-2 # vector. x = [[-1., 0, 1], [-11, 0, 11.]] # shape: [2, 3]. vla.prob(x).eval() # shape: [2]
Properties
- allow_nan_stats
- allow_nan_stats_dyn
- batch_shape
- batch_shape_dyn
- bijector
- bijector_dyn
- distribution
- distribution_dyn
- dtype
- dtype_dyn
- event_shape
- event_shape_dyn
- loc
- loc_dyn
- name
- name_dyn
- parameters
- parameters_dyn
- PythonObject
- reparameterization_type
- reparameterization_type_dyn
- scale
- scale_dyn
- validate_args
- validate_args_dyn